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 Posted: Wed Jul 28th, 2010 06:29 am
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mo1258
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Does anyone know how to calculate the standby losses on an electric tank water heater?

I would think manufacturers would publish this data but I can't find it anywhere.

Here's one suggested estimate but it seems to yield very low costs so I am skeptical that it is accurate:
Assume indoor tank with 72 degree ambient room temp, no flows in or out
.93 Energy factor = 236K WH per year @ $0.10 = $24 per year
.94 Energy factor = 189 KWH per year @ $0.10 = $19 per year

Your thoughts? Thanks!

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 Posted: Wed Jul 28th, 2010 06:52 am
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eleent
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Hello:  The Energy Guide label on a heater gives info on heaters and their energy use. See:  http://www.consumerenergycenter.org/home/appliances/waterheaters.html  One way to think of it is if a heater costs, say $200/year to operate according to the Guide and it has an Energy Factor of .93 that suggests (to me anyway) that 7% of the $200 (or $14) was lost.

A more accurate and difficult way would be to clock the energy used by the heater over a 24 or 48 hour period with no hot water usage.  The KWHs will be higher as there is plumbing attached, or lower if the room the heater lives in is warm ;)

Yours,  Larry

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 Posted: Mon Aug 2nd, 2010 03:57 pm
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mo1258
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Thanks for your reply to my post about Standby Losses. It is striking to me how "cheap" the losses are with a high efficiency electric.

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